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Formula for Determining Minimum Length of Fiberglass Filters for Correct Filtration |
TOTAL BPD
X 42(GAL)
_________________________
= GAL. PER DAYGAL. PER DAY
DIVIDED BY 1440 (MIN. PER DAY
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= GAL. PER MINUTEGAL. PER MN. (WITH FINE SAND)
DIVIDED BY _____GAL. PER FOOT
(SEE CHART TO RIGHT FOR GAL. PER FOOT)
_________________________________= _____________MINIMUM FEET OF FILTRATION NEEDED
FINE SAND..............................( .5 gpf) ROD PUMPS UP TO 2.00" (1.5 gpf)
ROD PUMPS 2 1/4 & UP (1.0 gpf)SUBMERSIBLE PUMPS
UP TO 500 BPD....................(1.5 gpf)
500 TO 1000 BPD..................(1.0 gpf)
1000 & UP ............................( .5 gpf)Example: 2000 BPD x 42 (gal) = 8,400 Gal. Per Day
8,400 Gal. Per Day 1440 (min. Per Day) = 58.34 Gal Per Min.
58.34 Gal Per Min. .5 (gal per ft) = 116.68 Minimum Ft. of Filter
116.68 = 5 Sections of filter (25 of total filtration per filter)STANLEY FIBERGLASS FILTERS ARE APPROXIMATELY 30 (9.15m) IN LENGTH AND HAVE APPROXIMATELY 25 (7.63m) OF TOTAL FILTRATION
(NOTE) SIZE OF CASING WILL DETERMINE THE AMOUNT OF FILTRATION AND THE VOLUME OF THE FLUID THAT CAN BE HANDLED.
Stanley Filter Company
10061 E. 52nd Street
Tulsa, OK 74146
| Phone |
800-545-9926 • 918-396-4141 |
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| Fax |
918-396-4200 |
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| Website | ||